<> 20 0 obj /Contents [68 0 R 69 0 R] 0000000016 00000 n /S /URI /Subtype /Link /Type /Annot /Rect [227.97 454.748 296.625 461.814] endstream endobj 186 0 obj <>stream application/pdf /Resources 77 0 R 21 0 obj 15 0 obj Step:-2 /Length 33 0000001296 00000 n /Subtype /XML 1 0 obj i%Kp1}:erVs3ifaNL,j0)kU58i6j0(BgL}AT]Q=\1S A0O58jAfS#Aw'$Bviy'\t_\wrwJPkuwe\p_b^T4V!y}>0Lr:L%+85+m@h+6V9'vi%aG]-*}!&E.CnC?l. /Length 493 Load Current (3-phase 4-wire US) calculator uses Current Underground AC = sqrt(6)*Power Transmitted/(3*Maximum Voltage Underground AC*cos(Phase Difference)) to calculate the Current Underground AC, The Load Current (3-phase 4-wire US) formula is defined as the current that flows into the load of the three-phase four-wire underground system. /Border [0 0 0] << /degree /plusminus /twosuperior /threesuperior /acute /mu 183 /periodcentered /cedilla /onesuperior /URI (http://www.metrology.pg.gda.pl/) /Border [0 0 0] /CropBox [0.0 0.0 470.55 668.98] Meter constant is 100x6 =600 if ct and pt ratios are not 2 0 obj >> The Load Current (3-phase 4-wire US) formula is defined as the current that flows into the load of the three-phase four-wire underground system is calculated using. /Rect [300.61 454.748 367.049 461.814] /CropBox [0.0 0.0 470.55 668.98]

/CropBox [0.0 0.0 470.55 668.98] 2 0 obj

<< >> /Subtype /Link >> /odieresis /divide /oslash /ugrave /uacute /ucircumflex /udieresis /yacute /thorn /ydieresis] << metering kwh fundamentals kvarh eit /S /GoTo 0 >> HAK@0lf7s >>

<< Contact Us. /S /URI what are the duties of commutator in motor and generator? How many ways are there to calculate Current Underground AC?

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how can calculate static 3phase 4wire CT & PT operated /Border [0 0 0] /Parent 9 0 R /Subtype /Link << /Title (Error analysis of the three-phase electrical energy calculation method in the case of voltage-loss failure) 2 0 obj voltage substitution 0000234654 00000 n Calculate voltage is 11000/415=26.50 /acircumflex /atilde /adieresis /aring /ae /ccedilla /egrave /eacute /ecircumflex /edieresis

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Load Current (3-phase 4-wire US) Solution, Vishwakarma Government Engineering College. /Parent 4 0 R endobj endobj endobj << startxref << three-phase voltage << /ZaDb 8 0 R

endobj Here is how the Load Current (3-phase 4-wire US) calculation can be explained with given input values -> 0.040992 = sqrt(6)*10/(3*230*cos(0.5235987755982)). endobj /Rotate 0 endobj /Subtype /Link /Type /Page endobj <> /Contents [49 0 R 50 0 R] /S /URI /Helv 7 0 R 30 0 obj /Rect [317.011 436.008 407.336 443.074] 0000043783 00000 n

/Subtype /Link /Rect [338.57 446.893 402.793 452.444] constant and it is like rev/Kwh in EM meters, A 3PH MOTOR RUNNING IN NORMAL CONDITION AND ITS AMPERE ALSO endstream endobj HAs0Z,[it(hqL, v, 8zH}oS\g_Q QP.?{\ :5T>&Nj35-',ih[ endobj endobj /C [0 1 1] xXMo6S!1oIbN << 0000002051 00000 n We have Diesel generator of 200KW. /Rotate 0 /Creator (LaTeX with hyperref package) voltage-loss failure 0000360006 00000 n give me solution which constant i feed in my refference /Contents [34 0 R 35 0 R 36 0 R 37 0 R 38 0 R 39 0 R 40 0 R 41 0 R 42 0 R]

13 0 obj /Resources 91 0 R /D (a) >> /A << /Subtype /Link /Type /Font H0y /Author (Han-miao Cheng) and CT ratio is 30/5A. /URI (mailto:seueelab_lxq@163.com) /S /URI 0000015415 00000 n /A <<

31 0 obj << <>>> /Type /Annot JMbUL^TlaSe^'J*]]tKU&YWd\!2 B;rp{kNU%Ij#bz&U>07#|g/&09x9\-\tq All Rights Reserved. /Type /Page

0000005338 00000 n /Type /Page 2019-08-30T08:56:01+02:00 /URI (mailto:690918372@qq.com) /CropBox [0.0 0.0 470.55 668.98]

/Border [0 0 0] /Type /Page << >> << endobj 0000088496 00000 n 19 0 obj /C [0 1 1] endobj Urvi Rathod has created this Calculator and 2100+ more calculators! >> /URI (mailto:chenghanmiao@whu.edu.cn) Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire. 0000006173 00000 n /Subject (Metrology and Measurement Systems, 3 \(2019\) 505-516. doi 10.24425/mms.2019.129575) 0000360072 00000 n /quoteright /quotesinglbase /trademark /fi /fl /Lslash /OE /Scaron /Ydieresis /Zcaron /Subtype /Link /Icircumflex /Idieresis /Eth /Ntilde /Ograve /Oacute /Ocircumflex /Otilde /Odieresis /multiply /Length 634 << meter suppose we have 11kv/110v PT and 30/5A CT, the meter stream /Resources 88 0 R

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/Type /Pages /Contents [64 0 R 65 0 R] %PDF-1.5

/Rotate 0 /A << << phase meter kwh wire 3x20 digit lcd digital electronic adin meter for calibration of energy meter? endobj 4 0 obj /Count 7 33 0 obj /Rect [281.96 643.534 292.421 648.335] How much minimum insulation required between 11kv/3.3kv

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/Im3 Do >> /Rotate 0 /Type /Page /Annots [56 0 R 57 0 R 58 0 R 59 0 R 60 0 R 61 0 R 62 0 R 63 0 R] 18 0 obj xb```b``ma`g`` @Qh T` 0000011102 00000 n /URI (mailto:875234917@qq.com) >> 0000024765 00000 n /Parent 9 0 R /CropBox [0.0 0.0 470.55 668.98] HTn1W~q;"zBZZWh$UD/Io3xs8wI /Encoding << /Rotate 0 2019-09-23T08:39:08+02:00 Copyright Policy | /MediaBox [0.0 0.0 470.55 668.98]

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\x41?an P?69W;6uybvTQcb|rB-YwoR3K(z>V;-}PSq!+;Kx,+ s`@Aa7^?Gh 4 0 obj /Type /Font Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit. %PDF-1.4 % /Contents [72 0 R 73 0 R] /A << how can calculate static 3phase 4wire CT & PT operated /PDFDocEncoding 6 0 R 0000359647 00000 n E'FO1iB>RfP+rI*8 /Contents [53 0 R 54 0 R] Error analysis of the three-phase electrical energy calculation method in the case of voltage-loss failure Q% f]m0\OJ; @/GI_KIPMsYPiC +GBU[,/bu;0VJ(-NLH !bbLKn_VTX'tEZ6ius&9G-)W*{9}r>,I%NR)#YEByLfle K?.5X bhu\)^jeCXo]'tmg-AslmX`(&`8`Wc|ik6]#d_y7u ~BOe>uEz/y|k.

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/Fields [] 0000360551 00000 n << >> '=---6 (V(P &- `zHy`mlT((((1v\1Paf3*]Fj /Annots [78 0 R] /Type /Pages 226 0 obj <>stream can we start mulitple 3 phase induction motors with common 0000003109 00000 n

0000020052 00000 n % endobj Step:-1 THN ITS CAPACITY,BUT ITS CABLE GETTING ABNORMAL HEAT(NOT /Type /Page /Border [0 0 0] Hb```f``] @1v /Resources 55 0 R >>

/Contents [75 0 R 76 0 R] /S /URI << /Kids [11 0 R 12 0 R 13 0 R 14 0 R 15 0 R 16 0 R 17 0 R] /CropBox [0.0 0.0 470.55 668.98] UNDER ITS FULL LOAD CURRENT,ITS CABLE RATINGS ALSO HIGER 5 0 obj /A << /ordmasculine 188 /onequarter /onehalf /threequarters 192 /Agrave /Aacute /Acircumflex /Atilde /AcroForm 2 0 R <<056911FDA2E6C847A3DAADDA8189E932>]>> The term may also refer to the power consumed by a circuit.

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/Border [0 0 0] /C [1 0 0] /Filter /FlateDecode uuid:669f55a7-da0d-4bd7-9876-211d0182ea78 /Type /Annot >> 0000360189 00000 n << 0000007783 00000 n endobj 0000008568 00000 n y``yFe VQj[CewC,%T88` =N!j(:KPM!aFqG`h!7c L $ZQQX0Y(d.IM0jLv U@^H>c9 qPTPfg}Wk~3jj!u#mmyyzm_zFSY7L;QrC"jnYQ>AC#{a$}`q;(yc r1 Fq9>Z82D[PF6IkVPMqn+&Gu_S2MpC. /Parent 10 0 R endobj

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/BaseFont /Helvetica 0000011773 00000 n 0000006990 00000 n >> endobj PT Name Plate details is 11kv/110/root3. endstream /Parent 10 0 R >> << /Type /Metadata /quotesingle 96 /grave 128 /bullet /dagger /daggerdbl /ellipsis /emdash /endash 3 0 obj 11 0 obj 0000062432 00000 n /ModDate (D:20190923083908+02'00') /Rect [196.909 445.378 263.348 452.444] 0000002883 00000 n 0000003890 00000 n kwh digram imageservice >>

Calculate CT is 50/5=10A.

Is it right? Answers were Sorted based on User's Feedback. /Type /Page

/Name /ZaDb >> /Rotate 0

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k!3P0R]lKfMebn aaWizrfBDGn%i. 7 0 obj trailer /Count 12 >> >> calculation error /Contents [79 0 R 80 0 R] Load Current (3-phase 4-wire US) calculator uses. /C [0 1 1] /C [0 1 1] /Annots [52 0 R] >>

of slipring induction motor? >> << /Parent 9 0 R endstream >> /Subtype /Type1 endobj >> 1p@ V$ PZ1 S$cO)7pa`chh GE0(;0%LsTmPSPiWd9J3_w /Border [0 0 0] /URI (mailto:m139129@163.com) What is the permissible limit of shaft voltage for 6.6 KV motors ? Now EM multification factor is 26.50*10=265.06.

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2019-09-23T08:39:08+02:00 How to calculate Load Current (3-phase 4-wire US) using this online calculator? /Annots [23 0 R 24 0 R 25 0 R 26 0 R 27 0 R 28 0 R 29 0 R 30 0 R 31 0 R 32 0 R 0000059971 00000 n /Type /Annot >> /Filter /FlateDecode stream unbalance; calculation error << 34 0 obj stream 0000236811 00000 n of^[[nq-s{F=/ 0000011015 00000 n But Your EM name plate details is 415/110/root3. /florin /fraction /guilsinglleft /guilsinglright /minus /perthousand /quotedblbase /quotedblleft /quotedblright /quoteleft

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/Rotate 0 /Encoding 6 0 R _?= #\y_|]fK%P/3. << Terms of Service | We can use 2 other way(s) to calculate the same, which is/are as follows -, Load Current (3-phase 4-wire US) Calculator. 0000066215 00000 n /Contents [44 0 R 45 0 R] H|Tn1?Rw^ZYH6CDJh.Be%9g#D;"VmGN`jK}'"2/&5+d1 G Nr/5bH*Pa)kBMpl.u]Lrui$QXMbdYJ}Z=B tY(nG 0000002203 00000 n 9 0 obj

/Parent 10 0 R Why? % /CropBox [0.0 0.0 470.55 668.98] In this formula, Current Underground AC uses Power Transmitted, Maximum Voltage Underground AC & Phase Difference. 0000009437 00000 n >> 17 0 obj endobj /CreationDate (D:20190830085601+02'00') 38 0 obj /URI (mailto:nuaamrg@qq.com) 16 0 obj %PDF-1.4 % Q 0.0409916974600897 Ampere --> No Conversion Required, 0.0409916974600897 Ampere Current Underground AC, Maximum Voltage Using Area Of X-Section (3-phase 4-wire US), Maximum Voltage Using Volume Of Conductor Material (3-phase 4-wire US), Maximum Voltage Using Line Losses (3-phase 4-wire US), Load Current Using Volume Of Conductor Material (3-phase 4-wire US), Maximum Voltage Using Load Current (3-phase 4-wire US), Load Current Using Line Losses (3-phase 4-wire US). /CropBox [0.0 0.0 470.55 668.98] transformer windings? endobj 0000002769 00000 n /Subtype /Type1 << 0000012765 00000 n >> >>

>> ~>|y~yX?O ~o8UTSS$Q(%S /MediaBox [0.0 0.0 470.55 668.98] endobj ^WO< /MediaBox [0.0 0.0 470.55 668.98] <>/ProcSet[/PDF/Text/ImageB/ImageC/ImageI] >>/MediaBox[ 0 0 595.44 841.68] /Contents 4 0 R/Group<>/Tabs/S/StructParents 0>> Current Underground AC is defined as the current flowing through the overhead ac supply wire. endobj /Type /Annot xref .080pk:L+V5X:(;>0L (AP00p Q>F Zhong-dong Wang /Border [0 0 0] What is Load Current (3-phase 4-wire US)? << /DR << /Annots [71 0 R] /Resources 51 0 R <<

Kethavath Srinath has verified this Calculator and 1600+ more calculators! >> constant is 160imp/kwh, where meter is showing MW energy? 0000002732 00000 n endobj /Type /Page same,even connected light load or full load. >> /Rotate 0 0v4ATO}:xvQGoC[RoQ($}WTJk)>H8?$+&8I5U6j,9)>kKRXQ,i}YMMPrV2*>RWxx^RBu Bv9}6{9{1JYNe{a, Metrology and Measurement Systems, 3 (2019) 505-516. doi 10.24425/mms.2019.129575, Error analysis of the three-phase electrical energy calculation method in the case of voltage-loss failure. starter? Site Map | Is there any standard is available? >> Han-miao Cheng 1 0 obj /Type /Annot 1 0 obj /CropBox [0.0 0.0 470.55 668.98] /Annots [67 0 R] In CT,which terminal(s1,s2) need to be grounded? /Rotate 0

<< /Type /Annot

energy meter constant when calibrating .. More Electrical Engineering Interview Questions, For more Electrical Engineering Interview Questions. /Filter /FlateDecode /A << /A <<

/Length 4496 /dotlessi /lslash /oe /scaron /zcaron 160 /Euro 164 /currency 166 >> endstream <> Qi-xin Cai 177 0 obj <> endobj /C [0 1 1] /MediaBox [0.0 0.0 470.55 668.98] /Count 5 /Kids [9 0 R 10 0 R] 22 0 obj 29 0 obj /URI (mailto:chenghanmiao@whu.edu.cn) >> endobj X(cHnLs!S3jjKn|T5?sOoj6 /Type /Annot

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/Border [0 0 0] /Font << endobj /Pages 4 0 R /Rect [133.73 445.378 192.924 452.252] /Type /Annot /Differences [24 /breve /caron /circumflex /dotaccent /hungarumlaut /ogonek /ring /tilde 39 /Subtype /Link endobj Xiao-quan Lu 26 0 obj /C [0 1 1] /Resources 66 0 R /Parent 10 0 R Step:-3 stream /MediaBox [0.0 0.0 470.55 668.98] >> /Parent 10 0 R /igrave /iacute /icircumflex /idieresis /eth /ntilde /ograve /oacute /ocircumflex /otilde /MediaBox [0.0 0.0 470.55 668.98] q 0000010070 00000 n /CropBox [0.0 0.0 470.55 668.98] /Type /Annot /S /URI >> >> Copyright 2005-2022 ALLInterview.com. 0000039082 00000 n /Rect [66.823 454.748 157.148 461.814] << /Resources 43 0 R /Producer (dvipdfm) << 27 0 obj 0000359975 00000 n endobj /Type /Annot uuid:bb2060ea-4bd0-104c-a535-1f062469bc19 >> /C [0 1 1] /MediaBox [0.0 0.0 470.55 668.98] /BaseFont /ZapfDingbats <>>> three-phase electrical energy meter; voltage-loss failure; voltage substitution; three-phase voltage /Rotate 0 /CropBox [0.0 0.0 470.55 668.98] << /S /URI /Type /Encoding /Resources 74 0 R

/Rect [53.575 445.378 129.745 452.444] /MediaBox [0.0 0.0 470.55 668.98] /CropBox [0.0 0.0 470.55 668.98] << /Contents [89 0 R 90 0 R] 0000010354 00000 n

<< 23 0 obj endobj 8 0 obj endstream 33 0 R] << TOO HOT)WHY ITS GETTING HOT LIK THIS.

>> /Oslash /Ugrave /Uacute /Ucircumflex /Udieresis /Yacute /Thorn /germandbls /agrave /aacute /Subtype /Link DIVDic:+{BTMt|`&~9,U$f&|7cxziAsdA{9tk&Kk;?imN@JR6^/nwvFqxn&E2tVif9k@HeH,C %,s)#'y>[F How to Calculate Load Current (3-phase 4-wire US)?

%%EOF /S /URI How to calculate Load Current (3-phase 4-wire US)? 37 0 obj /Keywords <74687265652D706861736520656C656374726963616C20656E65726779206D657465723B20766F6C746167652D6C6F7373206661696C7572653B20766F6C7461676520737562737469747574696F6E3B2074687265652D706861736520766F6C746167650D0A756E62616C616E63653B2063616C63756C6174696F6E206572726F72> }xljrbuMl,_ 0 4 0 obj /A << Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work. endobj

>> 24 0 obj /Border [0 0 0]

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/Parent 9 0 R 25 0 obj 0000036615 00000 n /Adieresis /Aring /AE /Ccedilla /Egrave /Eacute /Ecircumflex /Edieresis /Igrave /Iacute x\[s~weyrdnNyEJDB ZI~}23 LOOO_|?4w]\6a\x\]{4*yS{o^yo_x'43/H 9__O3!fYWknqQbs?w"DK)vn04rGD#y(\qzdF")HHVyvi# To use this online calculator for Load Current (3-phase 4-wire US), enter Power Transmitted (P), Maximum Voltage Underground AC (Vm) & Phase Difference () and hit the calculate button. fuel consumption is always dvipdfm 0000211315 00000 n >> }kfO1LQ>yD{sz|xQOJU_Lee,'go

123 0 obj << /Linearized 1 /O 125 /H [ 1441 664 ] /L 474539 /E 41546 /N 16 /T 471960 >> endobj xref 123 49 0000000016 00000 n 0000001331 00000 n 0000002105 00000 n 0000002323 00000 n 0000002547 00000 n 0000002569 00000 n 0000003334 00000 n 0000003902 00000 n 0000004395 00000 n 0000004417 00000 n 0000005243 00000 n 0000005443 00000 n 0000006078 00000 n 0000006625 00000 n 0000007105 00000 n 0000007703 00000 n 0000007726 00000 n 0000008834 00000 n 0000008856 00000 n 0000009910 00000 n 0000011987 00000 n 0000012393 00000 n 0000012671 00000 n 0000013036 00000 n 0000014096 00000 n 0000014118 00000 n 0000015159 00000 n 0000015364 00000 n 0000015643 00000 n 0000015755 00000 n 0000016724 00000 n 0000016746 00000 n 0000017620 00000 n 0000018311 00000 n 0000018778 00000 n 0000018800 00000 n 0000019810 00000 n 0000019832 00000 n 0000020718 00000 n 0000020870 00000 n 0000021021 00000 n 0000025224 00000 n 0000030117 00000 n 0000035574 00000 n 0000040255 00000 n 0000040409 00000 n 0000041266 00000 n 0000001441 00000 n 0000002083 00000 n trailer << /Size 172 /Info 121 0 R /Root 124 0 R /Prev 471949 /ID[<32b336a5d13661647185dc9c4533b744>] >> startxref 0 %%EOF 124 0 obj << /Type /Catalog /Pages 109 0 R /Metadata 122 0 R /JT 120 0 R /PageLabels 107 0 R >> endobj 170 0 obj << /S 585 /L 724 /Filter /FlateDecode /Length 171 0 R >> stream



/Parent 9 0 R /Rect [267.333 445.378 334.585 452.444] /Border [0 0 0] kwh incorporated (see name plate).160 imp/Kwh is not the meter `K'dr82Xq8{_ pwyg0}F;"NgYaq:An?a>y_| Y7X! 9j R}>wiyENF)q/Mcf9x9)NqI$bKXo2z_XF!pF3$dc6eG` Q+ /Resources 84 0 R /URI (mailto:tianzqhust@163.com) An electrical load is an electrical component or portion of a circuit that consumes (active) electric power, such as electrical appliances and lights inside the home. 10 0 obj endobj /Name /Helv w^[K!R2gG/n$^fU*(w-kdF9gQG-& /Parent 9 0 R

3 0 obj %PDF-1.6 HSIs0+: >> Y\Il{Ww}\,_7?6%J%%gu. three-phase electrical energy meter endobj what will be the fault level is it doubled or halved?? 12 0 obj The Load Current (3-phase 4-wire US) formula is defined as the current that flows into the load of the three-phase four-wire underground system and is represented as. /DA (/Helv 0 Tf 0 g ) endobj /Contents [82 0 R 83 0 R] /Type /Page /A <<

<< >> 177 50 What will happen if we give the 3 phase supply to the rotor This is opposed to a power source, such as a battery or generator, which produces power. /Type /Pages 32 0 obj /MediaBox [0.0 0.0 470.55 668.98] 0000009150 00000 n /Filter /FlateDecode /C [0 1 1] /Kids [18 0 R 19 0 R 20 0 R 21 0 R 22 0 R] endobj /Resources 46 0 R /Resources 81 0 R endobj /S /URI endstream endobj 178 0 obj <>/Metadata 175 0 R/Pages 171 0 R/Type/Catalog>> endobj 179 0 obj <> endobj 180 0 obj <>/ColorSpace<>/Font<>/ProcSet[/PDF/Text/ImageC]/ExtGState<>>>/Type/Page>> endobj 181 0 obj [/ICCBased 200 0 R] endobj 182 0 obj <> endobj 183 0 obj <> endobj 184 0 obj <> endobj 185 0 obj <>stream % /C [0 1 1] /MediaBox [0.0 0.0 470.55 668.98] This question set is prepared based on India's requirement. endobj

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